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Topic: Why would a decrease in temperature decrease the value of Kwater?  (Read 2473 times)

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Offline zygus

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In this equation:
H2O(l) + 57 kJ ↔ H+(aq) + OH-(aq)

Since it's endothermic, I thought it would proceed to the left to increase H2O when the temperature decreases. Could someone explain where I'm getting confused?

Also, since H2O is indicated to be a liquid, we wouldn't include it in the expression constant, correct? It would just be:
K = [H+][OH-]

Online Corribus

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Re: Why would a decrease in temperature decrease the value of Kwater?
« Reply #1 on: December 19, 2013, 02:04:17 PM »
Maybe this post I wrote some time ago will help you understand (ignore the first part addressed to Curiouscat):

http://www.chemicalforums.com/index.php?topic=68299.msg246224#msg246224
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

Offline zygus

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Re: Why would a decrease in temperature decrease the value of Kwater?
« Reply #2 on: December 19, 2013, 02:29:20 PM »
That's a fantastic answer, it makes a lot more sense now! Thank you so much!

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