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Topic: Probably a dumb question, buuut  (Read 3714 times)

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Offline dudebuddyguy

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Probably a dumb question, buuut
« on: January 10, 2014, 03:19:13 PM »
How do I figure this stuff out?

Quote
5. How many moles are there in 2.9 x 1023 molecules of carbon dioxide, CO2?

6. How many atoms are there in 0.349moles of Iron, Fe?

7. How many grams does 3.7 x 1024 atoms of sodium weigh?

This stuff is really throwing me off. That, and I need to show my work to get full marks and my calculator keeps responding to 1023 with 1e+23 and such which doesn't help me.

As for the Iron-related question, if this was asking me the mass of 0.349 moles of Iron, I'd just do 55.847 divided by 0.349 to get my answer....but it's asking about atoms. How the heck do you calculate atoms  ???

Offline kriggy

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Re: Probably a dumb question, buuut
« Reply #1 on: January 10, 2014, 03:42:12 PM »
Well this might be helpful to your problems
http://en.wikipedia.org/wiki/Avogadro_constant.
about the iron problem, how many atoms are in 1 mole?

Offline dudebuddyguy

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Re: Probably a dumb question, buuut
« Reply #2 on: January 10, 2014, 04:07:05 PM »
Well this might be helpful to your problems
http://en.wikipedia.org/wiki/Avogadro_constant.
about the iron problem, how many atoms are in 1 mole?

Yeah, so I read the Wikipedia article. Still confused as to how to properly calculate this stuff.

As for iron, I'm reading that there are 6.022 X 1023 atoms....which means I'm back at where I started, completely confused again.

Do I just ignore the 1023 and divide 6.022 by 0.349?

Offline eazye1334

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Re: Probably a dumb question, buuut
« Reply #3 on: January 10, 2014, 04:10:20 PM »
This stuff is really throwing me off. That, and I need to show my work to get full marks and my calculator keeps responding to 1023 with 1e+23 and such which doesn't help me.
1e+23 is just the calculator shorthand for 1023. They're the same thing according to the calculator.

Offline Borek

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Re: Probably a dumb question, buuut
« Reply #4 on: January 10, 2014, 04:36:08 PM »
Mole is just an overgrown dozen. If you have half a dozen of iron atoms, how many do you have? If you have half a mole of iron atoms, do the calculations exactly the same way, just the mole of iron atoms has 6.02×1023 atoms, not 12.
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Offline dudebuddyguy

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Re: Probably a dumb question, buuut
« Reply #5 on: January 10, 2014, 05:12:28 PM »
Mole is just an overgrown dozen. If you have half a dozen of iron atoms, how many do you have? If you have half a mole of iron atoms, do the calculations exactly the same way, just the mole of iron atoms has 6.02×1023 atoms, not 12.

Ok, so I was right when I assumed this was a simple division problem?

Because one iron mole has 6.02 x 1023 atoms. So .349 of a mole would obviously have less than half of 6.02

Offline Borek

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Re: Probably a dumb question, buuut
« Reply #6 on: January 10, 2014, 06:23:10 PM »
Half of a dozen is 0.5×12 - that's not a division.

iron mole has 6.02 x 1023 atoms. So .349 of a mole would obviously have less than half of 6.02

Less than half of 6.02×1023.
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Offline dudebuddyguy

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Re: Probably a dumb question, buuut
« Reply #7 on: January 10, 2014, 06:55:22 PM »
Half of a dozen is 0.5×12 - that's not a division.

iron mole has 6.02 x 1023 atoms. So .349 of a mole would obviously have less than half of 6.02

Less than half of 6.02×1023.

So like, 3.01 x 1011 (along those lines?)

Offline Borek

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Re: Probably a dumb question, buuut
« Reply #8 on: January 11, 2014, 03:38:02 AM »
Apparently part of your problem is simple math - you have no idea how to deal with the exponential part and what it means.

602 can be written as 6.02×100 = 6.02×102.

How much is half of that? Write it using all three methods. Does it require changing the exponent in 102, or is it enough to change the 6.02 part?
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