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Topic: CCl4 dipole moment calculation  (Read 10911 times)

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Offline Rutherford

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Re: CCl4 dipole moment calculation
« Reply #15 on: January 14, 2014, 10:44:59 AM »
But the assumption of no polarity of C-H bond gives zero dipole moment of C-H bond, so only C-X bonds have vectors of displacement.

Offline Corribus

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Re: CCl4 dipole moment calculation
« Reply #16 on: January 14, 2014, 10:46:51 AM »
Why would you assume C-H bond has no polarity?
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

Offline Rutherford

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Re: CCl4 dipole moment calculation
« Reply #17 on: January 14, 2014, 11:05:42 AM »
For easier guess. If I didn't assume it in the phenantrene problem, too I think that it would be much more complex to prove.

Offline Corribus

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Re: CCl4 dipole moment calculation
« Reply #18 on: January 14, 2014, 11:41:38 AM »
Well it seems to be a very poor assumption. The dipole moment of chloromethane (1.9 D) is almost twice that of chloroform (1.04 D).  Dichloromethane is somewhere in the middle (1.6 D).
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

jasaonline

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Re: CCl4 dipole moment calculation
« Reply #19 on: January 14, 2014, 11:52:16 AM »
I agree with what you say, I calculate as it is a bit difficult  >:D

Offline Rutherford

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Re: CCl4 dipole moment calculation
« Reply #20 on: January 14, 2014, 01:00:30 PM »
I see. Well, that question (which has bigger dipole moment CHX3 or CH3X) was in International Mendeleev Olympiad, and the answer was that they are equal, apparently wrong.

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