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Topic: Calculating Kc  (Read 2928 times)

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Offline bethanypamela

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Calculating Kc
« on: January 23, 2014, 10:55:36 AM »
Hello all, I'm totally new here. I'm completely stuck with how to calculate Kc, my tutor at college has given us this question:

For the equilibrium N2O4(g) ⇌ 2NO2(g)

Equilibrium concentrations are:
NO2(g) = 1.60 mol dm-3
N2O4(g) = 0.200 mol dm-3

Calculate Kc

Now, I'm not asking to cheat, this is the first time I've been truly stumped. It's probably something simple I'm missing... I'm completely clueless. Any help would be incredibly appreciated!
Thanks for reading :)

Offline Borek

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Re: Calculating Kc
« Reply #1 on: January 23, 2014, 12:18:52 PM »
What is the formula for the Kc for this system?
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Offline bethanypamela

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Re: Calculating Kc
« Reply #2 on: January 23, 2014, 12:36:50 PM »
Thanks for getting back to me!
We weren't given any other information but after attempting to understand, I think it is

Kc = (C)(D) / (A)(B) 2

But honestly this is admittedly why I am confused, if that isn't the required formula then I am lost.

Offline bethanypamela

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Re: Calculating Kc
« Reply #3 on: January 23, 2014, 12:38:01 PM »
Supposed to be square brackets there. Sorry.

Offline Corribus

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Re: Calculating Kc
« Reply #4 on: January 23, 2014, 12:49:27 PM »
Not quite.

http://en.wikipedia.org/wiki/Equilibrium_constant

Keep in mind you only have 1 reactant and 1 product in your case, so you will only have one term in your numerator and one in your denominator.
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Offline bethanypamela

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Re: Calculating Kc
« Reply #6 on: January 29, 2014, 04:19:46 PM »
Thank you so much for your help - I see now that I was over thinking it!

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