CH3-C≡C-CH3 HBR (excess) ?
I understand that this is an addition reaction with the use of the strong acid, HBr and that H and Br will be added to the reaction. The question is where exactly? The way our professor teaches us is that, in this case, the C with more H attached to it will receive the extra H, while the C with the least amount of H attached will receive the Br. The problem I have is that both Carbons have no H attached, just R groups.
After going over the problem, I checked the answer and it was: CH3-CHBR-CHBR-CH3. Can anyone help me with this?