[hallie3]

The octanol-water partition coefficient (Kow) for 3-chlorophenol (C6H5ClO) is 316.23. At equilibrium, the concentration of 3-chlorophenol (C6H5ClO) was found to be 2.43 x 10-3 M in octanol. Determine the mass (in g) of 3-chlorophenol in 36.8 mL of water.

My attempt:
(316.23)(2.43E-3 M) = 0.7684389 M
(0.7684389 M)(0.0368 L) = 0.0282785515 mols
(0.0282785515 mols)(128.5570 g/mol) = 3.64 g


But this is wrong. Am I approaching the question incorrectly? Any guidance is appreciated!

[Borek]

What you did looks OK to me. How do you know it is wrong?

[hallie3]

It was marked as incorrect on an assignment.