B. The concentration of the acetylsalicylic acid solution in the 2.00 mL aliquot:[/b]
My work: 0.002567894/0.002L = 1.283947 mol/L
And how are we going to know what is the problem and where did you got these numbers from?
But I can confirm your calculations - 0.002567894/0.002=1.283947, that's perfectly OK
BackgroundIn the experiment a solution of known concentration that contains an salicylato iron(III) complex is prepared by dissolving a known amount of aspirin tablet in sodium hydroxide, which is then added to a solution containing Fe3+(aq).
Absorbance measured using a colorimeter (A = .305). Using the Beer's law plot from part A (y = 672.73x + 0.0286), determine its concentration and then "back calculate" to find the number of mg of acetylsalicylic acid in the aspirin tablet. Compare with that on the label.
Steps I took:1. Put aspirin tablet in 125-ml flask
2. Added 10ml of 1 M NaOH(aq), boil
3. Transfer resulting solution to 250-mL volumetric flask, dilute with water to 250.00 mL
4. Perform gravity filtration on 10 mL
5. Pipet 2 mL of this solution into 50-mL flask, dilute to 50.00 mL mark with 0.02 M iron(III) chloride solution
6. Measured mean absorbance
7. Calculate concentration of tetraaquasalicylato iron(III) complex in this solution using slope of the line from Part A (given), calculate concentration of acetylsalicylic acid (in 250-mL flask), moles of acetylsalicylic acid, mass of acetylsalicylic acid in the tabletAlso, here's part A that I calculated
A. The concentration of the acetylsalicylic acid solution in the 50.00 mL sample:y = 672.73x + 0.0286
305 = 672.73x + 0.0286
x = 0.000410863 = 4.109*10^-4mol/L