I get it.
-You calculate the % dissociation as I have done in the original post.
-Then, for a base, % dissociation = x/[B ]0*100 with x=[BH+]=[OH-]. If you know [B ]0 you can calculate [OH-] the pOH and then pH.
- Knowing [B ]0, you do an ICE table, and solve for x=[BH+]=[OH-].
-Then you calculate % dissociation according to formula.
However, my question is still valid, at different temperatures, will the % dissociation be different?