I have three problems that I am struggling with:
CH3CH2CH2Br + CH3C(with three CH3's)attached to an 0-Na+
Is it really as simple as the Br and the Na "leaving" and the rest of the atoms attaching?
CH3C=OCH3 (a ketone) + H2
my friend thinks it is propane but I think it is propanol but am not sure where the second H goes.
thirdly, CH3C=OCH3 ( a ketone) + 3 NaOI gives me ? and then ? reacted with NaOH gives me ?
I think this might be an Iodoform reaction but am really lost here.
Thanks for any help.