Hi Big-Daddy, thanks for your reply. It has given me some direction of thought.
If I am right, I would take the reactants, lets say aminoacid A, aminoacid B and sugar S, add their free energy as a control. This value would be subtracted from all intermediate steps and the final product. However, given there are three water molecules coming off from the intermediate steps would I need to add their free energy values during the disassociation step and all subsequent steps? e.g.
A+B+S -> A'+B+S+H2O -> A'+B'+S+2H2O -> A'+B'+S'+3H2O (prime indicates a change a rearrangement in structure).
Thanks
Or, do I not balance the atoms, as in:
A+B+S -> A'+B+S -> A'+B'+S -> A'+B'+S'
Examples of a single disassociation i.e., reactant, product and a transition state, suggest that you DO include the free energy of the disassociated fragment when you calculate free energy differences.