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Topic: Help: normality and molarity of iodine and sodium thiosulfate  (Read 15623 times)

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Offline Asurath

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Hey,

Could anyone explain to me the following:
Why is 1N Na2S2O3*5H2O equal to 1M Na2S2O3*5H2O? Could you explain the process of conversion.
Why is 1N Iodine equal to 0.5M Iodine? Could you explain the process of conversion.

What to know:
Molar mass of Na2S2O3*5H2O = 248.18g/mol
Molar mass of I2 = 253.80g/mol
N - normality
M - molarity (molar concentration)

Offline Borek

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Re: Help: normality and molarity of iodine and sodium thiosulfate
« Reply #1 on: April 11, 2014, 12:58:42 PM »
Try to write reaction equations (half reaction equations to be precise).

See how many electrons are exchanged per S2O32- and per I2.
« Last Edit: April 11, 2014, 03:30:03 PM by Borek »
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