Good job. I will explain a bit:
From the mass spectra, M=86g/mol and we can deduce the -CH3 and -C3H7, -C and -O fragments. This is in agreement with the C-NMR spectrum. The shift of the C atom above 200ppm means that one C atom is connected to oxygen. From H-NMR it can be seen that the -C3H7 group is isopropyl. Using the rest of the information from H-NMR one will end up with 3-methyl-2-butanone.
May you now post another problem you want in a new topic, so we others try to solve it?