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Topic: Coprecipitation and its color, range of neutrality  (Read 2951 times)

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Offline Xenonman

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Coprecipitation and its color, range of neutrality
« on: May 06, 2014, 10:01:48 PM »
I am doubtful, yet again. I found these questions a while ago. I didn't bother then but I know it's time to ask CF about 'em.

Q1: When half a mole of K2CrO4 and one mole of Ag2NO3 are mixed in a liter of water:
(The Ag+ ions are enough to sink all the CrO42-, so the correct statement is: )
Solution remains colorless, and a red ppt is formed.

Q2: When a mole of K2CrO4 and one mole of Ag2NO3 are mixed in a liter of water:
(Not enough Ag+ to sink the CrO42-, so: )
A2: Solution becomes yellow, a red ppt is formed.

Q3: A solution of a pH=7.2 is:

a) Slightly basic

b) Neutral

c, d, e) Other nonsense

??? I am confused in this one. A basic chem book I had, those that give pH of substances without stating the importance of concentration and water as solvent, said the neutrality range is in between 6 and 8. Time passed and I learned about Kw and why pure water at STP is supposed to be purefectly neutral.

I suppose this one is somewhat subjective, and the so-called correct answer depends on the one that asks.
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Offline Borek

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Re: Coprecipitation and its color, range of neutrality
« Reply #1 on: May 07, 2014, 02:40:14 AM »
I would go with slightly basic.
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Offline Xenonman

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Re: Coprecipitation and its color, range of neutrality
« Reply #2 on: May 11, 2014, 12:26:51 AM »
 :(
Just noticed this thread is not related to coprecipitation. Yet I named it as if it was.
Just noticed I wrote silver(II) nitrate.

On a happier hand, slightly basic was the correct one.
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Offline Big-Daddy

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Re: Coprecipitation and its color, range of neutrality
« Reply #3 on: May 11, 2014, 10:35:53 AM »
Q2: When a mole of K2CrO4 and one mole of Ag2NO3 are mixed in a liter of water:
(Not enough Ag+ to sink the CrO42-, so: )
A2: Solution becomes yellow, a red ppt is formed.

Why is there not enough Ag+ to sink the chromate? One mole of Ag2NO3  :rarrow: 2 moles of Ag+ in solution, which is exactly what you need to precipitate out 1 mol of chromate as Ag2CrO4.

If you want to go the way of arguing by non-0 solubility product, then that will apply in the first case too - there will surely be some chromate left behind every time!

Offline Xenonman

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Re: Coprecipitation and its color, range of neutrality
« Reply #4 on: May 12, 2014, 07:43:11 PM »
This is just embarassing. First I write "Ag2NO3", which is not supposed to exist. Later on, I say I mistakenly wrote "Ag2CrO4". That one salt is actually correct.

Should you add actual silver(I) nitrate, Ag1(NO3)1, you'd sink only half of the chromate ions.
If you actually used the "Ag2NO3" thing, you'd end up sinking pretty much all of the chromate and silver ions. The only problem is the nonexistence of that salt. Only way to get some is having a typo while trying to write AgNO3 :P
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Offline Big-Daddy

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Re: Coprecipitation and its color, range of neutrality
« Reply #5 on: May 13, 2014, 06:16:20 PM »
This is just embarassing. First I write "Ag2NO3", which is not supposed to exist. Later on, I say I mistakenly wrote "Ag2CrO4". That one salt is actually correct.

Should you add actual silver(I) nitrate, Ag1(NO3)1, you'd sink only half of the chromate ions.
If you actually used the "Ag2NO3" thing, you'd end up sinking pretty much all of the chromate and silver ions. The only problem is the nonexistence of that salt. Only way to get some is having a typo while trying to write AgNO3 :P

How the **** I missed that and just proceeded with an explanation taking Ag2NO3 as a real salt, I will never be able to explain.

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