So you've only added 2e- to each? How did you control that -- adding just two, no more no less? Or is this purely hypothetical? And is the Au- ion stable? I'm sorry no experts have come in to help you, but I can't understand your question.
Thank you for your response!
So I suppose it would be ok to answer this question in a qualitative manner, rather than a quantitative manner with a discrete voltage or E_cell.
My thoughts on this are:
The Au 3+ has 6 electrons in its d orbital, adding 2 electrons will give it 8. Since the d orbital is most stable at 5 or 10 electrons, neither configurations of Au (3+ vs 1+) is particularly stable.
The Ti 3+ has lost both its electrons in d orbital and 1 electron from the 4s orbital (I think thats how it would loose them), so adding 2 electrons will make it have a filled 4s orbital and 1 electron in the 3d orbital (making it Ti 1+).
I think that the 1 electron in the d orbital of Ti 1+ might be less stable than the configuration of Au 1+ with 8 electrons in the d orbital. So my though is that the voltage potential of Au3+ should be a larger positive than Ti 3+ because it is easier to add 2 electrons? (Au3+ > Ti3+)
Does that sound correct, or am I totally off?