April 25, 2024, 01:49:25 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Percents,Molarity, and Normality  (Read 4628 times)

0 Members and 1 Guest are viewing this topic.

Pochiyama

  • Guest
Percents,Molarity, and Normality
« on: March 26, 2006, 07:39:47 PM »
Hello, I have a problem involving percents,molarity, and normality.
This is the problem:
Molarity of acetic acid=normality/mol of acetic acid*percent acetic acid=
Molarity of acetic acid=normality/mol of acetic acid*93.75%=
This is the reaction for acetic acid:CH3COOH + NaOH ---> NaOOCCH3 + H2O
I don't have the normality for acetic acid and I don't know how to get it all I know
is that acetic acid 1 equivalent. Help will be greatly appreciated.
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27663
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re:Percents,Molarity, and Normality
« Reply #1 on: March 27, 2006, 02:49:54 AM »
Please elaborate, you haven't posted any question here, just some unrelated information.
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Paradoxtom

  • Guest
Re:Percents,Molarity, and Normality
« Reply #2 on: March 27, 2006, 11:57:28 AM »
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links