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#### jokulsa

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« on: October 05, 2014, 11:00:02 AM »
1. How many moles of HF (pKa = 3.14) must be added to 500mL of 0.30M sodium fluoride (NaF) to give a buffer of pH 3.5? Ignore volume changes due to addition of hydrofluoric acid.

2. What is the molarity of CH3COO- in a buffer with a final pH of 5.20 if the concentration of CH3COOH is 0.25M? (pKa of CH3COOH is 4.7)

thanks

#### Hunter2

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« Reply #1 on: October 05, 2014, 11:15:33 AM »
Do you know Henderson Hasselbalch equation

#### jokulsa

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« Reply #2 on: October 05, 2014, 11:19:56 AM »
yeah I know it.
I think I managed to work out the second one, I don't really know where to start on the first..

#### Hunter2

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« Reply #3 on: October 05, 2014, 11:22:17 AM »
The first one is similar
develop HH-equation for it

#### jokulsa

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« Reply #4 on: October 05, 2014, 11:25:46 AM »
Is the 500mL given in the first question just there to confuse you?

If so, would the solution be

3.50 = 3.14 + log(0.30/[acid])

and then finding [acid] mathematically?

#### Hunter2

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« Reply #5 on: October 05, 2014, 11:27:48 AM »
Yes, but the value is wrong what does 0,3 M means

#### jokulsa

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« Reply #6 on: October 05, 2014, 11:34:47 AM »
Isn't this the [base]?

#### Hunter2

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« Reply #7 on: October 05, 2014, 12:01:07 PM »
M = molarity it has the unit mol/l, so how much mole you have in 500 ml

#### jokulsa

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« Reply #8 on: October 05, 2014, 12:11:26 PM »
I believe you would have 0.15 moles in 500mL

Why do you need to know this for this question?

#### Arkcon

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« Reply #9 on: October 05, 2014, 12:14:06 PM »
Write out the Henderson-Haselbach equation for us.  Then write it again, with the correct values in the correct places.  We'll look and see where you might be getting it wrong.  That's how this forum works: http://www.chemicalforums.com/index.php?topic=65859.0
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

#### Hunter2

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« Reply #10 on: October 05, 2014, 12:23:35 PM »
I believe you would have 0.15 moles in 500mL

Why do you need to know this for this question?

You have HH equation you have pH, pka and the amount of the moles of salt, now develop the equation please.

#### jokulsa

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« Reply #11 on: October 05, 2014, 10:36:21 PM »
the HH equation is

pH = pKa + log([base]/[acid])

using the values I have,

3.50 = 3.14 + log([base]/[acid])

I'm sorry but I still don't understand where and how the moles of NaF come into it.

#### Hunter2

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« Reply #12 on: October 06, 2014, 12:41:45 AM »
What is the base and what is the acid here.

#### jokulsa

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« Reply #13 on: October 06, 2014, 02:25:10 AM »
HF is the acid and NaF is the base

#### Hunter2

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