[rudiment274]

On average, one tablet of a certain antacid contains 500.0 mg sodium carbonate. If one tablet has a cost of 15 cents, calculate the cost of neutralizing hydrochloric acid in dollars per mol of HCl ($/mol).

Reaction: Na2CO3(s)+2HCl(aq)--->2 NaCl(aq)+H2O(l)+CO2(g)

Did I do this correctly:

500.0 mg Na2CO3 x 1 g/1000 mg x 1 mol Na2CO3/105.984 g Na2CO3 x 2 mol HCl/1 mol Na2CO3 x 2 mol H+/2 mol HCl = 0.009435386

15 cents x 1dollar/100 cents= $0.15

$0.15/0.009435386= $16/1 mol HCl

[Hunter2]

Sounds correct but you can calculate shorter.

1 mol hydrochloric  requires 1/2 mol sodium carbonate.

1/2 mol = 58 g  1 tablet is 0,5 g at means you need 106 of them.

106 *0,15$ = 15,9 ~ 16 $/mol