Help, I'm not sure if I'm doing this right...
"The volume of a sample of pure HCl gas was 189 ml @ 25 deg celsius and 108 mmHg. It was completely dissolved in about 60 ml water and titrated with an NaOH soln; 15.7 ml of NaOH soln were required to neutralize the HCl. Calculate the molarity of the NaOH soln."
Here's what I did:
NaOH + HCl --> H2O + NaCl
PV = nRT
(.142 atm)(.189 L) / (.082057)(298.15 K) = .001097 mol HCl
.001097 mol HCl * (1 mol NaOH / 1 mol HCl) = .001097 mol NaOH
Molarity (M) = .001097 / .0157 L = .0698 M for NaOH
Am I on the right track, or way off?
Tia!