[unsu]

Hi guys,

Please help me to figure out the product in this reaction: HIO₃ + HCl (conc., excess) 

I suppose that can produce H[ICl₄]·2H₂O

What do you think?

[unsu]

Here is my logic:

Assume the reaction produces iodine and chlorine:
2HIO₃+10HCl(conc) I₂+5Cl₂+6H₂O

I know, that Iodine and chlorine can react at 25 °C:
I₂+3Cl₂ 2ICl₃

I also know that ICl₃ can react with conc. HCl and water:
4H₂O + ICl₃  HICl₄·4H₂O

Summing up the reactions:
HIO₃ + 6HCl(conc., excess) + H₂O  HICl₄·4H₂O + 2Cl₂

Can it be true? If someone has access to SciFinder, could you please look up this reaction?

Or maybe it just stops on chlorine and iodine, i don't know. In the flowchart they mention excess HCl.. that's why I want to suggest HICl₄·4H₂O as the product