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Topic: Rhodium complexes question  (Read 1640 times)

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Offline elt2112

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Rhodium complexes question
« on: January 12, 2015, 04:22:49 PM »
I'm struggling with this question a bit.
So in Rh(PtBu3)2(H)(CO) the rhodium is in the +1 oxidation state and has 8 valence electrons. So thought that after reacting with C2F2 it would form Rh(PtBu3)2(F)(CO) as this has the same metal electron count, and there is no hydride. I'm a bit stuck with the next bit and can't seem to find anything about it to help.

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