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Topic: Heat Capacity  (Read 1879 times)

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Offline Ciubba

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Heat Capacity
« on: February 02, 2015, 10:25:03 PM »
Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium are needed to absorb 1 MJ of energy in the form of heat if the temperature of the sodium is not to increase by more than 10 degrees Celsius. Take Cp=30.8J /(mol K) for Na(l) at 500k

30.8 J/(mol k) * (1mol/23 g)=1.339 J/(g K)
Cp=H/(T x), where x is number of grams needed.

Solving this equation, I get 7.46*10^4 g; however, the book lists the answer as being 7.46*10^-4. Where did I go wrong?

Offline Borek

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Re: Heat Capacity
« Reply #1 on: February 03, 2015, 02:49:36 AM »
Without checking any math, their order of magnitude is blatantly wrong. You can't absorb MJ in mg without creating a hot plasma.
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Offline curiouscat

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Re: Heat Capacity
« Reply #2 on: February 03, 2015, 05:09:49 AM »
I get 74 kg.

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