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Topic: Equilibrium lab  (Read 1632 times)

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Offline purpTerp

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Equilibrium lab
« on: February 07, 2015, 01:37:27 PM »
I've been pounding my head against the wall the past couple of days due to having an issue with finding the equilibrium value from a concentration versus absorbance lab.

In the lab here are the readings I acquired:
TT#[Fe+3] init[SCN-] init[FeSCN+2] x[FeSCN+2]Absorbance
100.50M0N/A0
22.0*10-5M0.50M2.0*10-5MN/A0.17
34.0*10-5M0.50M4.0*10-5MN/A0.36
46.0*10-5M0.50M6.0*10-5MN/A0.55
58.0*10-5M0.50M8.0*10-5MN/A0.72
63.6*10-4M3.6*10-4MN/A1.76M (calculated in section below)0.135
73.6*10-4M7.1*10-4MN/A2.72M (calculated in section below)0.310
86.3*10-4M6.3*10-4MN/A3.14M (calculated in section below)0.385
96.3*10-4M9.4*10-4MN/A4.43M (calculated in section below)0.62

Calculation of of slope from excel graph (concentration versus absorbance):
Slope = 0.182

Calculation of concentration of [FeSCN+2] at Equilibrium
6)  C = (0.135 -(-0.186)) / 0.182 = 1.76M FeSCN
7)  C = (0.310 -(-0.186)) / 0.182 = 2.72M FeSCN
8)  C = (0.385 -(-0.186)) / 0.182 = 3.14M FeSCN
9)  C = (0.62 -(-0.186)) / 0.182 = 4.43M FeSCN

When I put the value of the equilibrium concentration into the ice table and solve for x, x is coming out as a postive value for FeSCN and a negative value when I solve for Fe and for SCN...help me Obiwan, you're my only hope!

Offline mjc123

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Re: Equilibrium lab
« Reply #1 on: February 07, 2015, 05:51:59 PM »
What on earth are you doing? Where did you get the numbers 0.182 and -0.186? It must be obvious that if you get an absorbance of 0.72 for a concentration of 8*10-5M, the slope is orders of magnitude different from 0.182. And how can you possibly get 1.76M complex when you started with 3.6*10-4M of metal and ligand, and the absorption is comparable to what you got with 2*10-5M?
Please explain exactly how you got those numbers - what you plotted against what, and what calculations you did. Then perhaps we can start to help you.

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