I've been pounding my head against the wall the past couple of days due to having an issue with finding the equilibrium value from a concentration versus absorbance lab.
In the lab here are the readings I acquired:
TT# | [Fe+3] init | [SCN-] init | [FeSCN+2] x | [FeSCN+2] | Absorbance |
1 | 0 | 0.50M | 0 | N/A | 0 |
2 | 2.0*10-5M | 0.50M | 2.0*10-5M | N/A | 0.17 |
3 | 4.0*10-5M | 0.50M | 4.0*10-5M | N/A | 0.36 |
4 | 6.0*10-5M | 0.50M | 6.0*10-5M | N/A | 0.55 |
5 | 8.0*10-5M | 0.50M | 8.0*10-5M | N/A | 0.72 |
6 | 3.6*10-4M | 3.6*10-4M | N/A | 1.76M (calculated in section below) | 0.135 |
7 | 3.6*10-4M | 7.1*10-4M | N/A | 2.72M (calculated in section below) | 0.310 |
8 | 6.3*10-4M | 6.3*10-4M | N/A | 3.14M (calculated in section below) | 0.385 |
9 | 6.3*10-4M | 9.4*10-4M | N/A | 4.43M (calculated in section below) | 0.62 |
Calculation of of slope from excel graph (concentration versus absorbance):
Slope = 0.182
Calculation of concentration of [FeSCN
+2] at Equilibrium
6) C = (0.135 -(-0.186)) / 0.182 = 1.76M FeSCN
7) C = (0.310 -(-0.186)) / 0.182 = 2.72M FeSCN
C = (0.385 -(-0.186)) / 0.182 = 3.14M FeSCN
9) C = (0.62 -(-0.186)) / 0.182 = 4.43M FeSCN
When I put the value of the equilibrium concentration into the ice table and solve for x, x is coming out as a postive value for FeSCN and a negative value when I solve for Fe and for SCN...help me Obiwan, you're my only hope!