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Topic: Reverse Osmosis  (Read 2909 times)

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Offline Ciubba

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Reverse Osmosis
« on: February 17, 2015, 08:09:56 PM »
Assuming that seawater at 20°C is a 1.1 Mc solution of NaCl (aq), calculate how many liters of seawater are required to prduce 15 liters of freshwater at 20°C with an applied pressure of 75 bar.

Π=RTMc, so Mc=(75 bar)/ [(.08314 L bar K-1 mol-1)*293 K], which simplifies to 3.07882 Mc.

I need to know how many liters of water would have to be removed from seawater in order to produce that level of concentration, so Mc1V1=Mc2V2, where Mc1 is 1.1 and Mc2 is 3.07882. For convenience, I'm going to make V2=1, so that I will know how much seawater produces one liter of fresh water. V1=2.7989 L.

I need 15 liters of fresh water, so I multipied that value by 15 to get 42 L; however, the book lists the correct answer as being 23 L. Where did I go wrong?

Offline Borek

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Re: Reverse Osmosis
« Reply #1 on: February 18, 2015, 02:55:40 AM »
Van 't Hoff factor.
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Offline Ciubba

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Re: Reverse Osmosis
« Reply #2 on: February 18, 2015, 05:48:19 PM »
Van 't Hoff factor.
Hmm, where would I need to consider that? Mc1V1=Mc2V2 is fine as NaCl has the same i factor as NaCl and I see no other place involving Mc.

Offline Borek

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Re: Reverse Osmosis
« Reply #3 on: February 19, 2015, 02:50:04 AM »
Mc1V1=Mc2V2 is fine as NaCl has the same i factor as NaCl and I see no other place involving Mc.

What about the other equation you listed?
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Offline Ciubba

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Re: Reverse Osmosis
« Reply #4 on: February 19, 2015, 05:44:57 PM »
It can't be Π=RTMc as I intentionally solved for Mc instead of M as the concentration of the salt water was given in colligative molar, so that just leaves the multiplication by 15, right?

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