Well the are between 2 electron withdrawing groups, does this tell you anything?
it doesnt, i have my organic chemistry book[klein] by myside and my computer, [what should i look on them to understand this better]?
What i figured out is that the Br will leave, and when it does, the carbon on the buttom will be left with a (+) charge making it easy for the oxigen to make a bond[by changing it self to O (-) using the electrons on the double bond next to it].
the things i dont understand, are:
firstly what is the function of NaH and THF on the reaction.
secondly is that ive been tought Carbons cant have more that four bonds, but on the product side of the mechanims you have the carbon with a double bond, a bond with the nitrile and i the two hydrogens leaving you with a total of 5 bonds...
So how do i get rid of the extra H, and how do i form a double bond between the carbons??
How do i make ithe bond between the O (-) and the C (+) be formed on the "back" of the molecule??
Ps:im sorry for my english, and my lack of knowledge.