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Topic: Degree of Sulfation of 2-Methylimidazole  (Read 1867 times)

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Offline MOF

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Degree of Sulfation of 2-Methylimidazole
« on: March 16, 2015, 02:18:03 AM »
Hello guys,
I'm new of the forum, nice to meet you all.
Actually I'm trying to solve a stoichimetric problem but no results. I was wondering if someone has already encountered a problem like this:
I have to calculate the sulfation degree of 2-methylimizole. The reaction is a simple sulfation on an aromatic ring that should be occurred in position 4 of the imidazolic ring. I started the reaction treating 1,205g of 2-mim
with an excess of concentrate sulfuric acid. I got 7,591g of product (sulfated 2-mim).
Any help would be really great.

Thx

Offline discodermolide

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Re: Degree of Sulfation of 2-Methylimidazole
« Reply #1 on: March 16, 2015, 06:47:39 AM »
Start by drawing the reaction equation.
And draw the structures of starting material and product.
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Offline MOF

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Re: Degree of Sulfation of 2-Methylimidazole
« Reply #2 on: March 16, 2015, 10:48:02 PM »
Sorry, i probably didn't provide much data to solve the problem.
I'm actually working on Metal organic frameworks and i'm trying to sulfonate a MOF in two ways: Sulfation of the mof after the creation of the network and sulfation of the ligand to use consequently to create the mof. My problem is keeping the molar ratio between the metal and the ligand constant, but if I use the ligand with the sulfonic group the molar mass changes and I have to consider that. Anyway the reaction is the one in the pic attached.

Thanks for the help.

Offline discodermolide

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Re: Degree of Sulfation of 2-Methylimidazole
« Reply #3 on: March 17, 2015, 02:43:55 AM »
OK; now you need to work out the number of moles of starting material you have, and the number of moles of product, based on the weights you provided.
Also work out the number of moles you would expect for a bis-sulfonated product.
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