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Topic: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?  (Read 8463 times)

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Offline koalizard

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How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« on: March 25, 2015, 03:33:28 AM »
Hi I'm having trouble with this question on my assignment. According to my notes I should be doing

0.238 moles divided by 0.0526000 litres (52.6ml) and the answer I get is 4.52471482989.

Would this be correct, and if it's not could someone point me in the right direction? Thankyou
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Offline Hunter2

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Re: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« Reply #1 on: March 25, 2015, 03:42:02 AM »
No. Do you know for what M stands for?
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Offline koalizard

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Re: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« Reply #2 on: March 25, 2015, 03:46:49 AM »
I thought it was M for moles
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Offline Hunter2

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Re: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« Reply #3 on: March 25, 2015, 03:51:42 AM »
M stands for the molarity and its unit is mole/l. The letter for moles is n, which unit only mol is.

With this knowledge you can calculate now .
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Offline koalizard

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Re: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« Reply #4 on: March 25, 2015, 03:57:00 AM »
Does this mean I calculate 0.238 (concentration) x 0.0526 (volume) = 0.0125 moles?
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Offline Hunter2

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Re: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« Reply #5 on: March 25, 2015, 03:58:03 AM »
Yes exactly.
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Offline koalizard

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Re: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« Reply #6 on: March 25, 2015, 04:02:17 AM »
Ok thank you so much. I am kind of struggle town atm, I am doing 1st year chemistry and have never done chemistry in my life
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Offline koalizard

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Re: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« Reply #7 on: March 25, 2015, 04:07:57 AM »
Quote from: Hunter2 on March 25, 2015, 03:58:03 AM
Yes exactly.

Sorry again my next question is:
How many moles of NO3- ions are present in 215 mL of a 0.56 M Al(NO3)3 solution.

Does this follow the same formula? 0.56 x 0.0215 = 0.01204 moles?
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Offline Hunter2

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Re: How many moles of HCl are present in 52.6 mL of a 0.238 M HCl solution?
« Reply #8 on: March 25, 2015, 04:53:02 AM »
Genereally yes, you have to use this formula, but you have to consider how many moles Nitrate correspond to Aluminium nitrate. What does the small 3 tell us. And how many liter is 215 ml. 0.0215 l is wrong.
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