[Sis290025]

Calculate the enthalpy change, for the reaction shown below.
2 A + B --> C + D
The heats of formation values are A= -90 kJ/mol; B= 48kJ/mol;C= 139kJ/mol; and D= -26kJ/mol.

deltaG* = [-26 + 139]kJ - [48 kJ - 2(-90)]kJ
= [113]kJ - [228]kJ
= -115 kJ


Calculate the entropy change, for the reaction shown below.
A + 2B --> 2C + D
The molar entropy values are A= 87 J/mol; B= 162J/mol;C= 52J/mol; and D= 210J/mol.

deltaS* = [2(52) + 210]J - [2(162) + 87]J
= [104 + 210]J - [87 + 324]J
= -97 J

Thanks.

[tamim83]

Hey looks pretty good to me.  Except enthalpy is delta H and entropy is delta S.