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### Topic: Concentration Question  (Read 1660 times)

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#### cvc121

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##### Concentration Question
« on: May 25, 2015, 07:10:50 PM »
Hi,

What is the concentration of Li if there is 200mL of Li2SO3 solution?

Here is my attempt:

First,I converted 200mL to 0.2L.
Then I calculated the Li concentration to be (1.5M)(2) = 3.0M.

Should I now multiply the 3.0M by 0.2L? Does the 0.2L even need to be considered?
Not sure what to do next.

All help is very much appreciated! Thanks!

#### Corribus

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##### Re: Concentration Question
« Reply #1 on: May 25, 2015, 10:14:07 PM »
Then I calculated the Li concentration to be (1.5M)(2) = 3.0M.
You lost me with this. Where did you get 1.5M from? Did you forget to include part of the question wording?
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

#### cvc121

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##### Re: Concentration Question
« Reply #2 on: May 25, 2015, 11:10:07 PM »
Yes. Forgot to mention that in the question. The solution is 1.5M.

#### Corribus

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##### Re: Concentration Question
« Reply #3 on: May 26, 2015, 12:38:14 AM »
Presuming Li2SO3 fully dissociates into ions, how many moles of lithium ions will there be for every more of Li2SO3? You seem to have already figured this out, and that would be the end of it. The volume is inconsequential to the concentration. It's basically a decoy to throw you off.
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman