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Topic: Formation of lactone  (Read 2835 times)

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Offline cseil

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Formation of lactone
« on: June 08, 2015, 10:58:35 AM »
Hi, I found this exercise.
He asks me to find out why the product has the same configuration.

There's a carbocation and a sp2 carbon, so I can't understand why the oxygen attacks only from one side of the plane.
Can you help me please?

Offline discodermolide

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Re: Formation of lactone
« Reply #1 on: June 08, 2015, 11:04:45 AM »
Try diazotisation of the NH2 as a start, then think about how you might retain the configuration.
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Offline mjc123

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Re: Formation of lactone
« Reply #2 on: June 08, 2015, 11:11:19 AM »
The product you have drawn has inversion of configuration. Is that right?

Offline cseil

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Re: Formation of lactone
« Reply #3 on: June 08, 2015, 01:27:14 PM »
The product you have drawn has inversion of configuration. Is that right?
Yes, S to R.

The start is the diazotisaton, but it's an aliphatic compound so the N2 goes out and a carbocation is formed. Is that right?
This was my start.

Offline Dan

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Re: Formation of lactone
« Reply #4 on: June 08, 2015, 02:07:45 PM »
it's an aliphatic compound so the N2 goes out and a carbocation is formed.

How do you think the carbonyl adjacent to your predicted carbocation would affect its stability?
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Offline orgopete

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Re: Formation of lactone
« Reply #5 on: June 08, 2015, 03:45:15 PM »
Hint, since the stereochemistry is not lost, a carbocation is probably not an intermediate. Hint #2, alpha-???
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Offline cseil

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Re: Formation of lactone
« Reply #6 on: June 09, 2015, 05:21:42 AM »
The carbocation is not stable at all considering the presence of C=O. But I cannot understand how to continue. I can see only the formation of the carbocation and the attack from the O-. Otherwise the lactone is not formed.

Offline discodermolide

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Re: Formation of lactone
« Reply #7 on: June 09, 2015, 06:08:17 AM »
Try making the alpha lactone, and decide what this does to the stereochemistry. then see if you can convert that to the desired product
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