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Assuming that the total volume does not significantly change, when mixing ROH with water:Mixing aqueous KOH 1N and alcoholic KOH 1N,
we get an initial mixture of KOH 1N per total volume unit that will immediately be transformed (ionic reaction) to (say) KOH 0.995 N and ROK 0.005 N per total volume and (say) KOH 1.98 N and ROK 0.02 N per ROH volume or a ratio 0.99/0.01
The relative concentrations of KOH and ROK may change by further dilution with either water of ROH or their mixture but the concentration ratio 0.99/0.01 will remain constant, when calculated per ROH partition.
As a reminder, the latter discussion refers to anhydrous ethanolic KOH.
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