I don't know if I understand your question.
So, I calculated the molarity of TMOS stock solution: M= ( 0,99 x 1023 g/L)/ 152,22 g/mol = 6,65 mol/L
And now I don't know how to calculate the volume of TMOS (liquid reagent- stock) that I need to add in 1 mM in order to have a final concentration of 1 M.
Is correct i used the equation of dilutions In this case? Mi x Vi= Mf x Vf. ( Mi= 6,65 mol/L and Mf= 1 mol/L)
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Don't know if it is correct because I am used HCl ( 1 mM), and not water. ...