The question is:
Butane has a vapour pressure of 47.156 kPa at 253 K, and 149.03 kPa at 283 K. Is butane gaseous or non-gaseous under the following conditions:
Temp. = 253 K Pressure = 1 atm
Temp. = 253 K Pressure = 2 atm
Temp. = 283 K Pressure = 1 atm
Temp. = 283 K Pressure = 2 atm
So firstly, I have searched what vapour pressure means. And from what I read, vapour pressure is the pressure of the vapour of a liquid at equilibrium in a closed system. And can only affected by temperature.
So since butane has a vapour pressure of 47.156 kPa at 253 K, at 253 K and 1 atm the vapour pressure of butane would still be 47.156 kPa. However, I am not sure how the external pressure would affect the physical state of butane. Could someone explain this? Also does the 1 atm mean that in a closed system, the pressure in it is 1 atm?