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Topic: desilylation by 0.5 eq of TBAF?  (Read 2267 times)

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Offline google470

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desilylation by 0.5 eq of TBAF?
« on: July 29, 2015, 04:26:09 AM »
It is difficult to understand the reason why 0.5 eq TBAF can remove the TBDPS group completely in the refs (table 3, entry 2) below. :-\ :-\ :-\
Could you tell me why? Thanks

Reference: Synlett, 2000, 9, 1306-1308 Link

Excerpt attached.

Mod edit: Full text link removed due to questionable legality. Replaced with referenced excerpt. Dan
« Last Edit: July 29, 2015, 08:14:20 AM by Dan »

Offline Dan

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Re: desilylation by 0.5 eq of TBAF?
« Reply #1 on: July 29, 2015, 07:49:50 AM »
Hint: Table 4, entry 6
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Offline google470

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Re: desilylation by 0.5 eq of TBAF?
« Reply #2 on: July 29, 2015, 08:31:47 AM »
Hint: Table 4, entry 6

Thanks a lot.

So... ...it seems F-  serve as a catalyst, TBSF <--->  TBS + F-, then the TBS moiety was trapped by H2O, and F- would attack another TBSOR... ...

Offline Dan

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Re: desilylation by 0.5 eq of TBAF?
« Reply #3 on: July 29, 2015, 10:44:59 AM »
That seems reasonable. It is quite a complicated reaction in terms of mechanism - it is not exactly clear what the active desilylating species is (notice table 4, entry 1).

I guess there is a complex equilibrium:

R3SiF + H2O + AcO-  ::equil:: R3SiOH + HF + AcO-  ::equil:: R3SiOH + F- + AcOH  ::equil:: R3SiOAc + F- + H2::equil:: and so on

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Offline google470

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Re: desilylation by 0.5 eq of TBAF?
« Reply #4 on: July 29, 2015, 11:46:48 PM »
That seems reasonable. It is quite a complicated reaction in terms of mechanism - it is not exactly clear what the active desilylating species is (notice table 4, entry 1).

I guess there is a complex equilibrium:

R3SiF + H2O + AcO-  ::equil:: R3SiOH + HF + AcO-  ::equil:: R3SiOH + F- + AcOH  ::equil:: R3SiOAc + F- + H2::equil:: and so on

so complicated...

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