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Topic: Gravimetric Stoichiometry  (Read 5373 times)

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ohsosweet

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Gravimetric Stoichiometry
« on: April 20, 2006, 11:35:08 PM »
I need to find the mass of water vapor formed when 1.00g of butane C4H10 is burned in a lighter
« Last Edit: April 21, 2006, 12:24:02 AM by mike »
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Offline mike

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Re: Gravimetric Stoichiometry
« Reply #1 on: April 20, 2006, 11:44:32 PM »
Is this just a statement or are you asking a question?

Write an equation for this reaction.
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ohsosweet

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Re: Gravimetric Stoichiometry
« Reply #2 on: April 21, 2006, 12:22:12 AM »
asking a question
i not sure what the equation is
C4H10   + O2   + heat  ----->    4CO2   +   5H20
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Offline mike

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Re: Gravimetric Stoichiometry
« Reply #3 on: April 21, 2006, 12:28:51 AM »
Okay, but your equation is not balanced yet:

C4H10 + O2  -----> CO2 + H2O

Do you know how to balance this? I will give you a clue, double the values you have for CO2 and water and then go from there.
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ohsosweet

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Re: Gravimetric Stoichiometry
« Reply #4 on: April 21, 2006, 12:37:03 AM »
so ...2C4H10   + 13O2   + heat  ----->    8CO2   +   10H20

is that right?
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Offline mike

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Re: Gravimetric Stoichiometry
« Reply #5 on: April 21, 2006, 12:48:16 AM »
Yes :) Good work.

Now you need to know the molecular weight of butane.
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ohsosweet

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Re: Gravimetric Stoichiometry
« Reply #6 on: April 21, 2006, 12:53:29 AM »
ok thanks..i think i got it from here
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Offline mike

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Re: Gravimetric Stoichiometry
« Reply #7 on: April 21, 2006, 12:54:08 AM »
No problem. Just remember always start with a balanced equation ;-)
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