The enthalpieS of formation. Find a cycle (or two paths) involving carbon, hydrogen, liquid methane, gaseous methane where all transformations involve a known heat but the vaporization. In a closed transformation cycle, deduce the vaporization from the rest.
Why divide by a mass, if you want to deduce a molar heat from molar heats?
If willing to refine the question, you could note that from data at 298K, you will obtain a vaporization heat at 298K too, which is not propane's boiling point under 1atm. If some day you need the vaporization enthalpy at a different temperature, do almost as previously:
find a cycle involving the vaporizations at both temperatures and other known operations. In this case, it needs the heat capacities of the liquid and the gas between both temperatures. Deduce the latent heat at the desired temperature from the one at the known temperature.