Given that I have 120mL of 0.007M Acetic acid what will be the pH if I were to add 20ml of 3M HCl?
Am I gonna do an ice tble for this if so here is what I'll do:
HOAc
H
+ + OAc
-I 8.4x10
-3 0.06mol 0
C -x +x +x
E 8.4x10
-3 -x 0.06+x x
Ka=1.75 x10
-5Ka= (0.06 +x)(x)/ (8.4x10
-5-x)
x= 2.45x10
-8[H
+] = 0.06+ 2.45x10
-8 =0.060 M
pH= -log[H
+]
pH=1.22
Its this even correct>>>?