[aaazureee]

So I have a confusing question about electrochemistry calculation
The electrochemical cell below at 25 degree C and 1atm(pretty much standard)
Half-cell A: 1mol dm-3 FeSO4(aq) and 1mol dm-3 Fe2(SO4)3 (Pt rod)
Half-cell B: 1mol dm-3 CuSO4 (aq) (Cu rod)
The question is to calculate the Ecell of the reaction but i dont know how to do it with 2 substance at 1 half-cell? so half-cell a has fe2+ and fe3+ while half cell b has cu2+. Maybe someone can shed me some light on this question. Thanks

[Hunter2]

You have two cells. Fe²⁺/Fe³⁺ (Platinum is innert connector to the wire), and you have Cu²⁺/Cu⁰

Get the potentionals from each half cell and combine it.