[Da4gotten]

The percent by mass octane is quantified for an organic sample via GC using decane as the
internal standard. A GC vial containing 0.5023 grams organic sample and 0.2384 grams
decane is prepared and analyzed, returning peak areas of 119,993 for octane and 83755 for
decane. If a response factor of 2.50 from previous work analyzing octane with a decane
internal standard is used, what is the percent by mass octane in the organic sample?

using formula: area of analyte signal/mass of analyte = F(area of internal standard signal/mass of internal standard signal)

(11,993/X)=(2.50)(83755/0.2384g) = 0.1366 g octane /0.5023g organic sample x 100 = 27%

Is this correct?