Hello guys, i am new to this forum. I am stuck on a chemical problem for quite a while now, and have decided to ask for some help since i could not solve it on my own. So, here's the thing.

If 9 * 10^{-2} mol/L NH_{3} is consumed in 3 minutes according to the reaction 4NH_{3}(g) +5O_{2}(g) = 4NO(g) + 6H_{2}O(g) what is the **rate of formation** of NO(g) and H_{2}O(g) in mol/L * s.

The problem here is, that in order to calculate the rate of formation, i need either the mass (m) / amount of substance (n) / number of particles (N) / volume (v) and i have none of those. The only things i have are the concentration (c) of NH_{3} which is 0.09 and molar mass of NH_{3} (which is 17). Could any of you help me somehow, or tell me some equations to find some of those missing constants? I could never say thank you enough if so. Cheers, Filip!