The problem: A sample containing Na
2HPO
4 and NaH
2PO
4 · 2H
2O weighs 2.15 g. The sample was dissolved in 30 mL HCl (0.1 molar). The excess of HCl is titrated with 8.75 mL NaOH (0.2 molar), using methyl orange as an indicator. Find percent composition of the mixture (by mass).
Attempt: If both the hydrogen- and dihydrogen phosphate are fully protonated to phosphoric acid. After calculations, this proves not to be logical, as I get a negative result... Also, this approach (which my professor wants) does not make sense to me, as titration with sodium hydroxide solution would lead to deprotonation of phosphoric acid itself, making it impossible to calculate anything.
So the way I approach this is that I can think of it in this manner: upon addition of excess diluted HCl, this happens only:
HPO
42- + H
+ H
2PO
4-As the value for this constant it 1/K
a2 = 1.6exp7, you can say the reaction is quantitative, and the existing H
2PO
4- ion do not interfere the equlibrium. Basically, it was a fictive buffer all until dissolved in the mineral acid. As methyl orange was used as an indicator, the end point of the titration is when the excess HCl has reacted, so the quantity of hydrogen phosphate ions is: 0.03 mL * 0,1 M - 0.00875 mL * 0.2 M = 0.00125 mol, so the mass of Na
2HPO
4 is 0.1775 g, which is 8.26%.