We have the equation

2 NaCl => 2 Na + Cl_{2}

what means 2 mole of sodiumchloride will convert to 2 mole of sodium and 1 mole of chlorine gas, which is a two-atomic molecule.

We have 16 t NaCl this must fit to x tons sodium + y tons chlorine.

Molar mass of NaCl is 58,5 g/mol, Na 23 g/mol and Cl_{2} 71 g/mol Units can be extended to kg/kmol

The moles must be equal

So u can write n = m(NaCl)/xM(NaCl) = m(Na)/yM(Na) = m(Cl_{2})/zM(Cl_{2})

x,y,z= stoechiometric coefficients. x = 2 , y = 2, z =1

m(NaCl) = 16 t = 16000 kg

n = 16000 kg/x 58,6 kg/kmol = 273,5 kmol/x

m (Na) = n *y M(Na) m(Na) = 273, 5kmol/x * y* 23 kg/kmol = (y/x) 6290,5 kg, y =x = 2, Result 6290,5 kg

m(Cl_{2}) = n*z(M(Cl_{2}) m(Cl_{2}) =273,5 kmol/x * z * 71 kg/kmol =(z/x)* 19418,5 kg , x =2 z =1

m(Cl_{2}) `=1/2 *19418,5 =9709,25 kg

6290,5 kg + 9709,25 kg =15999,75 kg ~ 16 t