Hello! So I want to know why adding water to an eqalibrim reaction does change our Q value. This is what my book says:
2 H2O(l) 2 H2(g) + O2(g) .. Kc = [H2]2 [O2]
"Adding H2O(l) will have no effect on the equilibrium because the reactant is a liquid. Notice that the concentration of H2O(l) is not a part of the equilibrium constant expression. Since the concentration of product gases do not change when H2O(l) is added, Q is still equal to K and there is no driving force for the system to change. As long as some liquid is present to establish the equilibrium, adding more will have no effect on the concentration of products."
Thank you for your time.