[jMacKenzie]

Would someone please confirm my structure . . . I'm not feeling very confident.  I'm trying to draw
 (1S,2R)-1-bromo-1-sec-butyl-2-methylcyclohexane.  I end up with the bromo group and the methyl group both axial (one up, one down) on adjacent carbons.

[Archer]

Would someone please confirm my structure . . . I'm not feeling very confident.  I'm trying to draw
 (1S,2R)-1-bromo-1-sec-butyl-2-methylcyclohexane.  I end up with the bromo group and the methyl group both axial (one up, one down) on adjacent carbons.

Take each chiral centre individually, personally I would start with the centre bearing the proton for the sake of simplicity. How are the remaining three carbon atoms prioritised?

[Alwin Kristen]

I think your structure isn't exactly right. Check the first stereosenter, where the bromine is attached. Is bromine up or down?

[Guitarmaniac86]

Unless I am missing something fundamental, the structure in the OP is correct.

[Alwin Kristen]

I think that OP has 1R instead of 1S

edit: gave it a second tought and you are right Guitarmaniac86. I priored substituents wrong at first. OP has right structure IMO.

[discodermolide]

According to ChemDraw the name is (1S,2R)-1-bromo-1-(sec-butyl)-2-methylcyclohexane.
So as drawn the carbon bonded to Br is (S).