Me and a coworker were arguing about this today. He says that you'd need to use M1V1 = M2V2 --> assuming 14.8 N ~14.8 M then 14.8 M NH4OH(V2) = 0.1 M NH4OH(500 mL) = 3.38 mL of 29.7% NH4OH. I found an online calculator that says you'd actually need 6.57 mL of NH4OH. My own calculation gave the same result and other sites I've found support this # too.
First off which is right?
Second, based on my understanding, the only way that 29.7% NH4OH could be 14.8 N is if the 14.8 is reported as NH3. Why would a label for 29.7% NH4OH report the normality as NH3, when the molecular formula is reported as NH4OH? Is this just convention, or am I missing something?