November 06, 2024, 03:11:26 AM
Forum Rules: Read This Before Posting


Topic: Help Balancing Ion-Electron Redox Half-Reaction  (Read 2268 times)

0 Members and 1 Guest are viewing this topic.

Offline bobbybeck

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Help Balancing Ion-Electron Redox Half-Reaction
« on: April 16, 2016, 08:17:49 PM »
Hello. I was wondering if anyone could help me balance this equation using the methods I said in the subject line. Thanks!

IO3-(aq) + I-(aq) = I3-(aq)

This is an acidic reaction, I don't know if that is obvious or not.

Offline Burner

  • Full Member
  • ****
  • Posts: 198
  • Mole Snacks: +15/-2
  • Gender: Male
  • Chem-is-try
Re: Help Balancing Ion-Electron Redox Half-Reaction
« Reply #1 on: April 16, 2016, 10:04:53 PM »
Hello. I was wondering if anyone could help me balance this equation using the methods I said in the subject line. Thanks!

If I didn't misread your post, you want to balance this quation using half-equation method, right?(Just for confirmation - not saying this method is wrong)

IO3-(aq) + I-(aq) = I3-(aq)

Obviously, you have IO3-(aq) and I-(aq) from the start, and these two chemicals will both be oxidized/reduced to I3-(aq). So, you need to balance the following two half equations:

IO3-(aq)  :rarrow: I3-(aq)

I-(aq)  :rarrow: I3-(aq)

Try to proceed from here.
Year 1 science student in HKUST and a Chemistry geek.
If I make any mistakes in the forum, please don't hesitate to correct me as I want to learn.

Sponsored Links