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Topic: halohydrin formation - stereochemistry  (Read 5497 times)

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Offline plu

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halohydrin formation - stereochemistry
« on: May 09, 2006, 08:58:59 PM »
Will halohydrin formation always occur with the hydroxide attaching to the more substituted carbon, regardless of the fact that the more substituted carbon is more hindered to SN2 attack?  For example, the reaction of 1-methylcyclohexene with Br2 in H2O will result first in a bromonium intermediate, then attack by a water molecule at C1.  Will this reaction result in the production of 1-methyl-2-bromocyclohexanol even though C2 is less hindered than C1?

Offline wereworm73

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Re: halohydrin formation - stereochemistry
« Reply #1 on: May 09, 2006, 10:05:22 PM »
Hmmm...Doesn't the halonium ion resonate and cause a stronger partial + charge on the most highly substituted carbon bonded to the halogen?  With a tertiary carbon, I think the partial charge might be strong enough to offset the additional steric hindrance, and the water molecule that attacks the carbon to leave behind the OH group is only a weak nucleophile...It doesn't fit the profile for a classic SN2 reaction. 

Offline movies

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Re: halohydrin formation - stereochemistry
« Reply #2 on: May 10, 2006, 05:50:07 PM »
It's the same argument that you use to explain any Markovnikov addition process.  The carbocation structure is more stable when the cation resides on a more substituted carbon atom, so more stability leads to ultimately more positive charge on that carbon and therefore more electrophilicity.

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