When a complete combustion of methanol happens, you get this reaction:
4NH
3(g) + 7O
2(g)
4NO
2(g) + 6H
2O(l)
ΔH
f(NH
3(g)) = -46,0 kj/mol.
Use the formation of entalphies and figure out the reaction of entalphy. Tables in my book is attached below:
Can anybody share their calculations?