[iEmerald]

Hi,

I really want to understand how such questions are solved ( https://imgur.com/gallery/bzoVb ) ..

According to what did we organize it as 4d, 5s and 5p? What are the numbers on top of those and why did 5s became 0 in the second step in the middle ..

The problem is our textbook simply jumped to this example without even explaining what is what ..

[amirtavakoli92]

The electron configuration for Ag is: [Kr] 4d10 5s1 5p0. The p orbitals are empty. the numbers on top of the orbital name represents the number of electrons in those orbitals. so 5s1 is equal to 1 electron in s orbital in the 5th shell. 4d10 means that there are 10 electron in d orbitals (d subshell) in the 4th main shell.
in the picture you attached, the configuration for outermost shell is shown by orbital diagrams.
in the middle one, it is Ag+ cation, that is, one electron lower than silver atom. So you should eliminate an electron form electrons in the outermost energy level of an atom — in the energy level that is farthest away from the nucleus.(highest n-shell)