A 25.0 sample of HCl is neutralize by 26.5mL of 0.155 M NaOH. Calculate the molarity of the HCl solution. (Hint: In this case, Molarity of HCl is MA in moles/liter of HCl.)

The equation would be M1V1/M2V2

(0.155M)(26.5mL)/(25.0mL)=.164M Is this right?

Do I multiply my answer by HCl moles which is 36.46g/mole?