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Topic: How to calculate the molarity of HCl solution?  (Read 5849 times)

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Offline jennie28

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How to calculate the molarity of HCl solution?
« on: May 19, 2016, 10:30:19 AM »
A 25.0  sample of HCl is neutralize by 26.5mL of 0.155 M NaOH. Calculate the molarity of the HCl solution. (Hint: In this case, Molarity of HCl is MA in moles/liter of HCl.)

The equation would be M1V1/M2V2
(0.155M)(26.5mL)/(25.0mL)=.164M Is this right?
Do I multiply my answer by HCl moles which is 36.46g/mole?
« Last Edit: May 19, 2016, 10:40:57 AM by jennie28 »

Offline sjb

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Re: How to calculate the molarity of HCl solution?
« Reply #1 on: May 19, 2016, 10:40:32 AM »
A 25.0  sample of HCl is neutralize by 26.5mL of 0.155 M NaOH. Calculate the molarity of the HCl solution. (Hint: In this case, Molarity of HCl is MA in moles/liter of HCl.)

What does it mean for this solution to be neutralised?

Offline jennie28

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Re: How to calculate the molarity of HCl solution?
« Reply #2 on: May 19, 2016, 10:43:33 AM »
To make the acid neutral

Offline sjb

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Re: How to calculate the molarity of HCl solution?
« Reply #3 on: May 19, 2016, 11:00:55 AM »
The equation would be M1V1/M2V2
(0.155M)(26.5mL)/(25.0mL)=.164M Is this right?
Do I multiply my answer by HCl moles which is 36.46g/mole?

The first part seems sensible. What would the units be after you have multiplied M by molar mass? How would this differ, if for instance you had Ca(OH)2 and not NaOH?

Offline jennie28

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Re: How to calculate the molarity of HCl solution?
« Reply #4 on: May 19, 2016, 11:43:03 AM »
Would I divide .164 M/ 1 liter= .164 M/Liters of HCl?

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